Cyclic Quadrilaterals

Prove the statement ' A Cyclic Parallelogram is a rectangle'.

If $ABCD$ is a Cyclic Trapezium and $AB=4 \mathrm{cm}$ and $BC=6 \mathrm{cm}$, then find $CD$.

From the given figure find the measure of angles $m$ and $n$.

The oblique sides of a cyclic trapezium are

$ABCD$ is a cyclic trapezium such that $AD \parallel BC$ and $\angle B=70°$, then the value of $\angle A$ and $\angle C$ is

$ABCD$ is a cyclic trapezium, $AD$ is parallel to $BC$. If $\angle ABC=75°$, find $\angle BCD$.